How to replace just the first found space with tab for all lines in a variable?

[Jim Ault]

On May 26, 2011, at 3:11 AM, Alex Tweedly wrote
>
> How embarrassing !!
> I tested this in my message box, and had a typo (almost invisible  
> space) in the input data.
> Sorry Jim (and Keith).

Nah, Alex, not embarrassing at all.
This is how everyone learns some of the odd rules.
This is probably only the second time you made a typo after all these  
years on the list.
and I can't remember the first one :-)

So many of us enjoy quickly answering questions and solving puzzles,  
it is natural that bloopers will happen.
I think the key is to have fun with them.

Jim Ault
Las Vegas

>
> On 26/05/2011 04:39, Jim Ault wrote:
>> On May 25, 2011, at 8:41 AM, Alex Tweedly wrote:
>>
>>> Beware this will get the (possibly) wrong result for some data.  
>>> For instance, a comma will terminate a word, so
>>> a,b def
>>> will give you a key of "aTABb def"
>>> rather than a key of "a,TABdef"
>>>
>> Punctuation is not considered a word delimiter, so the comma will  
>> remain attached to the string.
>>
>> put word 1 of "a,b def" into msg
>> -- I get "a,b" using Rev 3.5
>>
>> In fact, if the words have trailing commas, the punctuation is  
>> considered part of the word
>>
>> put word 2 of "He spoke, therefore he was heard"
>> =>  the 6 chars     'spoke,'
>>
>> put word 2 of "nice ,,and,,,,,,,,,, warm"
>> =>   ,,and,,,,,,,,,,
>>
>> put word 2 of "really ...-and_,;]/><? truly"
>> =>  ...-and_,;]/><?
>>
>> Hope this helps
>> Jim Ault
>>