Math problem

[Bob Sneidar]

Thanks all. Some ingenious ways of going about it. Never ceases to amaze me when I see all the ways of doing something when I thought there was only 1. :-)

Bob


On Feb 17, 2012, at 11:49 AM, Peter M. Brigham, MD wrote:

> On Feb 17, 2012, at 12:20 PM, Geoff Canyon Rev wrote:
> 
>> function roundUp x,i -- rounds x up to the next i
>>  return ((x - .00001) div i + 1) * i
>> end roundUp
> 
> Works except for values like 4.000000001.
> 
> Try this instead. It's a sort of a trick to avoid using a conditional construction, though the logic is conditional in structure, but does it in one line. I couldn't find a way of doing it using just LC's math functions, maybe someone else can.
> 
> function roundUp x
>   return trunc(x) + char itemoffset((x mod 1 > 0),"true,false") of "10"
> end roundUp
> 
> -- Peter
> 
> Peter M. Brigham
> pmbrig at gmail.com
> http://home.comcast.net/~pmbrig
> 
> 
> _______________________________________________
> use-livecode mailing list
> use-livecode at lists.runrev.com
> Please visit this url to subscribe, unsubscribe and manage your subscription preferences:
> http://lists.runrev.com/mailman/listinfo/use-livecode