Order of operators
m.schonewille at economy-x-talk.com
Thu Aug 27 10:18:24 EDT 2009
This is about a calculation with potentially hundreds of parameters. I
don't think that parsing the formula to reduce the number of brackets
will be fast enough to make the exercise worthwhile.
I'm building up the formula in a repeat loop, one operator at a time:
I can leave brackets out when a + or - is added, but I wish I could
leave them all out. I assume a calculation without brackets is faster,
because the symbols between brackets are parsed first.
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On 27 aug 2009, at 15:55, Jim Bufalini wrote:
> Not sure about no brackets without multiple puts into vars (which
> should add
> time), but for less brackets:
> put ((1*2+3-4)/5)^6
> Answer is the same due to brackets, precedence of operators (*
> before +) and
> left to right calculation (+ before -).
> But, I'm curious. How much time do brackets add? It's something I
> thought of.
> Aloha from Hawaii,
> Jim Bufalini
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