QT: How do I subtract clocktimes?

[Brian Yennie]

As an alternative "manual" method, you could also do the subtraction  
yourself. This is untested, but should work - and gives you total  
control over any conversion oddities. Just subtract the individual  
parts, and if you get a negative minutes portion, roll off another hour.

set the itemDelimiter to "."
put (item 1 of t1 - item 1 of t2) into item 1 of t3
put (item 2 of t1 - item 2 of t2) into item 2 of t3
if (item 2 of t3 < 0) then
   subtract 1 from item 1 of t3
   add 60 to item 2 of t3
end if


> William,
>
> The easiest way to do time and date math is to convert the times or  
> dates to seconds, do the calculations, then convert them back to  
> time or date. So to subtract hours (This is assuming time format  
> for the system is set properly; U.S. would use colons instead of  
> dots):
>
>  put "16.00" into t1
>  put "7.30" into t2
>  convert t1 to seconds
>  convert t2 to seconds
>  put t1 - t2 into tDiff
>  put tDiff div (60*60) into tDiffHours
>  put tDiff mod (60*60) into tDiffMins
>  put tDiffHours & "." & tDiffMins into tTimeDiff
>
> This is off the top of my head, not tested. But this approach  
> should work just fine.
>
> Regards,
>
> Devin
>
>
> Devin Asay
> Humanities Technology and Research Support Center
> Brigham Young University
>
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---
Brian Yennie
QLD Learning