Can't pass array function result as parameter
dburgun at dsl.pipex.com
Thu Mar 30 11:00:37 EST 2006
Depending on how you have coded it, there will be 2 copies of the
if you do this in the library:
function LibChangeArray theArray,theKey,theData
put theData into theArray[theKey]
put LibGetArray() into myArray
Then there will be one copy of the array stored in gLibArray (in the
library stack) and one stored in myArray (in the client stack).
LibChangeArray() will change the copy in myArray and then return, the
mouseUp handler will return and myArray will be destroyed.
In order to fix this you'd have to add the following line to
put theArray into sgLibArray
AFAIK, this means the array is copied twice, there may be a way to
save this copying by use of the "@" keyword but if so I haven't been
able to figure out how to do it.
Hope this helps
All the Best
On 30 Mar 2006, at 05:42, James Spencer wrote:
> Can anyone confirm this problem. I'm getting an array from a
> function in a library. I modify that array and then pass it to a
> handler also in the library. The debugger is showing that the
> modified array is valid and contains what it should but the
> parameter in the library is shown as empty. I've found a work
> around by copying the elements of the array to a new array and
> passing that but obviously this should not be necessary.
> Bugzilla shows a bug in the Windows version of 2.7 that is probably
> the same bug, #3411, but there, the poster stated that they could
> resolve the problem by simply placing the array they are getting
> from the function into a temporary variable and then passing that
> where I'm seeing the problem even when I put it into a temp (as I'm
> necessarily doing as I modify the array before passing back to the
> library again.
> James P. Spencer
> Rochester, MN
> jspencer78 at mac.com
> "Badges?? We don't need no stinkin badges!"
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