Wildcard? replaceText, offset?

Ben Rubinstein benr_mc at cogapp.com
Wed Apr 29 08:09:54 EDT 2020

Not sure what 'previous post' referred to. Reg ex "[0-9]+" (or equivalently 
"\d+") would match one or more integers.

Provided this is the first/only instance of the pattern, I would have thought 
that regex does provide the neatest solution, e.g.:

	put "(" & iNewNumber ")" into tReplacement
	put replaceText(tOldString , "\(\d+\)", tReplacement) into tNewString

On 26/04/2020 20:15, dunbarx--- via use-livecode wrote:
> Pay no attention to the previous post, which only dealt with a single integer. Sloppy.
> THIS old fashioned method works, though:
> on mouseUpput offset("(",yourString) into startCharput offset(")", yourString) into endCharput random(999) into char (startChar + 1) to (endChar -1) of yourStringend mouseUp
> Craig
> -----Original Message-----
> From: doc hawk via use-livecode <use-livecode at lists.runrev.com>
> To: How to use LiveCode <use-livecode at lists.runrev.com>
> Cc: doc hawk <dochawk at gmail.com>
> Sent: Sun, Apr 26, 2020 2:41 pm
> Subject: Re: Wildcard? replaceText, offset?
> On Apr 26, 2020, at 11:24 AM, Rick reasoned
>> In the middle-end part of the string I have “(x)” where x represents some integer.
>> it could be (4) or (10) or (5) etc.
> If you’re certain that this is the only, or even the first, integer, a regular expression search and replace or [0-9]+  would  do the trick.

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