Date Calculation
Andrew Kluthe
andrew at ctech.me
Thu Nov 29 15:23:54 EST 2012
That's what I'm looking for! Great.
However, I tried what I think I am supposed to do in the script below
and my dates are about three days off.
This function is supposed to give me the date for monday of the week
where the date paramater is.
If the paramater is empty it uses todays date.
function DetermineWeek pDate
if pDate is empty then
put the date into sDate
else
put pDate into sDate
end if
convert sDate to dateItems
answer sDate
set the itemDelimiter to ","
put item -1 of sDate into sDay
switch sDay
case "2" --Monday
put 0 into sDiff
case "3" --Tuesday
put 1 into sDiff
case "4" --Wednesday
put 2 into sDiff
case "5" --Thursday
put 3 into sDiff
case "6" --Friday
put 4 into sDiff
case "7" --Saturday
put 5 into sDiff
case "1" --Sunday
put 6 into sDiff
end switch
put item 3 of sDate into sDayOfMonth
put sDayOfMonth - sDiff into sNewDay
put sNewDay into item 3 of sDate
answer sDate
convert sDate to date
return sDate
end DetermineWeek
For instance leaving the paramater blank should provide me today
(11/29/12) with a date of 11/26/12 but instead I am returned 11/23/12.
Maybe I don't properly understand your process for doing this.
On Wed, Nov 28, 2012 at 10:03 AM, Devin Asay <devin_asay at byu.edu> wrote:
>
> On Nov 28, 2012, at 8:33 AM, Andrew Kluthe wrote:
>
>> Hey Ya'll,
>>
>> I thought I had this figured out but I don't and I am not sure where
>> to go from here.
>>
>> I want to retreive the date for the monday and the sunday of the current week.
>>
>> For instance, if it were today 11/28/2012 then I would want to return
>> 11/26/2012 and 12/2/2012 . I was trying to leverage Sara R's Date &
>> Time library, but even with all those lovely functions I still can't
>> get what I am after. I know there has to be a simpler way of doing
>> this than the broken mess I was coming up with. How would you tackle
>> this problem?
>
> Andrew,
>
> Convert the date to date items, then using the last item (numeric day of the week), calculate how many days between today and the preceding Monday and the following Sunday.
> Once you have that, just add (or subtract) the difference to item 3 of the date items, then reconvert to the date. The convert command will adjust everything properly in the case of transitions between months and years.
>
> If you can't figure it out, let me know and I'll dig through some code where I had to do this and post it.
>
> HTH
>
> Devin
>
>
>
> Devin Asay
> Office of Digital Humanities
> Brigham Young University
>
>
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--
Regards,
Andrew Kluthe
andrew at ctech.me
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