Math problem

[Peter M. Brigham, MD]

On Feb 17, 2012, at 12:20 PM, Geoff Canyon Rev wrote:

> function roundUp x,i -- rounds x up to the next i
>   return ((x - .00001) div i + 1) * i
> end roundUp

Works except for values like 4.000000001.

Try this instead. It's a sort of a trick to avoid using a conditional construction, though the logic is conditional in structure, but does it in one line. I couldn't find a way of doing it using just LC's math functions, maybe someone else can.

function roundUp x
   return trunc(x) + char itemoffset((x mod 1 > 0),"true,false") of "10"
end roundUp

-- Peter

Peter M. Brigham
pmbrig at gmail.com
http://home.comcast.net/~pmbrig