m.schonewille at economy-x-talk.com
Sat Feb 13 15:30:01 CST 2010
That's right. You double-click a file in Windows and Windows starts
another instance of the executable for that file. In that executable,
you catch the relaunch message. If file $1 exists, don't return any
value from the relaunch handler. The new instance will be terminated
and the message is passed on to the already running instance.
Note that the message is sent to the already running instance. The
already running instance decides whether the new instance of the
executable is to be terminated or not.
Economy-x-Talk Consulting and Software Engineering
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Op 13 feb 2010, om 22:15 heeft Scott Rossi het volgende geschreven:
> Recently, Mark Schonewille wrote:
>> There are several intresting posts about this subject in the archives
>> of this list. On of them can be found here http://qurl.tk/4x You
>> probably have that info already, since it is Ken's.
> Thanks Mark. The one (?) item I'm unclear on is the script example:
> on openStack
> put $0 into theAppPath
> put $1 into theDocToOpen
> answer "The doc to open is: " & theDocToOpen
> end openStack
> Wouldn't this execute only when the app is first launched? What
> message is
> sent to the app while the app is running? Or am I just not
> the way this works?
> Thanks & Regards,
> Scott Rossi
> Creative Director
> Tactile Media, UX Design
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