snapshot problem 1

Thomas McGrath III mcgrath3 at
Thu Dec 4 15:04:10 EST 2008

Ok, thanks guys, I was stuck on "it" or "the result" since the docs  
state that snapshot 'creates' a new image. When ever I create a new  
object via script it places the long id of that object in "it".

last image will work.....


Tom McGrath III
Lazy River Software
3mcgrath at

iTunes Library Suite - libITS
Information and download can be found on this page:

On Dec 4, 2008, at 12:47 PM, Jim Ault wrote:

> Think of it just like
> first card, last card, last field, last button
> Assuming you do not change the layer order, you newest image will  
> always be
> the highest layer number.
> If there is an image on the card, then there is a first and last  
> image.
> If there is one image on a card, the first and last image is the same.
> Hope this helps
> Jim Ault
> On 12/4/08 8:38 AM, "Thomas McGrath III" <mcgrath3 at> wrote:
>> When you import a snapshot - How do you get the name of the newly
>> created image that the snapshot is placed in?
>> From the Docs:
>> Comments:
>> The import snapshot command creates a new image in the center of the
>> current card and places the snapshot in the image.

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