number of colornames?

[wayne durden]

Hi Mark & Joe:

I don't want to beat a dead horse or belabor a point, but:

the number of lines of colornames() returns 552

however as I iterate through the lines using something like

line i of colornames()

by the time I am at 552 I am nowhere near the end...

I realize what is probably going on is that there are often 4 or so
variations on a single name like firebrick, firebrick1, etc.

What is confusing is why the "number of lines" and "line i of" aren't in
agreement.  And assuming I do want to get all of the variations, how should
I set up the loop other than "repeat with i=1 to the number of lines of
colornames()"?

thanks again
Wayne

On 2/11/07, Mark Schonewille <m.schonewille at economy-x-talk.com> wrote:
>
> Wayne,
>
> Not every colour has a name. There are (apparently) 552 named colours
> and many more unnamed colours, assuming that there are approximately
> 255^3 different colours. The colorNames function returns all of the
> 552 named colours.
>
> There used to be a PANTONE colours library stack in the user
> contributions collection on the Revolution site, which could be
> interesting for you, but this collection is no longer available.
> Maybe someone still has that stack and is willing to make it available?
>
> Best,
>
> Mark
>
> --
>
> Economy-x-Talk
> Consultancy and Software Engineering
> http://economy-x-talk.com
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>
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>
> Op 11-feb-2007, om 21:44 heeft wayne durden het volgende geschreven:
>
> > Hi Joe:
> >
> > I actually discovered that fact too by adding additional numbers to
> > my loop
> > (actually 15 more cds with 100 colors each til the end).  But the
> > problem is
> > why does the number of lines of colornames() yield fewer?  The
> > number of
> > lines of colornames yields 552, but there look to be about 2000'ish
> > colornames?
> >
> > My suspicion is that this is related to associative array with same
> > name
> > issues but not sure.  More importantly how ahead of time would I
> > structure
> > the loop to take me to the end?  Perhaps a while not "" I guess?
> > Thanks
> > Joe!
> >
> > wayne
>
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