Stripping trailing spaces from a string

[Jim Ault]

On 3/4/06 8:00 PM, "Jim Witte" <jswitte at bloomington.in.us> wrote:

> How can I use a RegEx to strip trailing white-space?  I tried:
> 
> get matchText(theExpr, "(.*)\s*", theExpr)
> 
> where theExpr is "0025E95C mov      r5, r0                          "
> _______________________________________________

   put "(.*[^\s])" into regEx --trims spaces from right
  get matchText(strr,regEx,strr)

Basically says capture the whole string and come back until the character is
not a "word delimiter", not necessarily a space.  If you only want spaces to
qualify then use

put "(.*[^\ ])" into regEx --trims spaces from right
(note the space char after the "\")


put "([^\s]+)" into RegEx  --matches only the first word

Basically says capture the characters as long as it is not a "word
delimiter".


Ken has MUCH better experience and even gives time trial results :-)


Jim Ault
Las Vegas