Arithmetic operations on dates ?

[Bill Vlahos]

I believe it is 2am.

Bill Vlahos

On Mar 6, 2005, at 8:56 AM, Michael D Mays wrote:

>  put "2005,2,29,0,0,0,0" into someDate
>  convert someDate to dateItems
>
> someDate will be "2005,3,1,0,0,0,3"
>
> If I say
>
>  put "2005,3,6,23,59,59,0" into aTimeDate
>  add 1 to 1 to item 6 of aTimeDate
>  convert aTimeDate to long date
>
> aTimeDate is
>   'Monday, March 7, 2005'
>
> What days is Rev starting the day at 1 am or 2 am or 3 am?