How to find the offset of the last instance of a repeating character in a string? (Geoff Canyon)

Brian Milby brian at milby7.com
Sun Nov 4 23:56:20 EST 2018


Here's an image of the stack in my fork of the repo:
https://github.com/bwmilby/alloffsets/blob/bwm/bwm/stack_allOffsets_card_id_1018.png


On Sun, Nov 4, 2018 at 10:07 PM Brian Milby <brian at milby7.com> wrote:

> I’m working on an update to the stack now. Moving buttons to the left side
> to make it easier to add more.
>
> Thanks,
> Brian
> On Nov 4, 2018, 10:02 PM -0600, Mark Wieder via use-livecode <
> use-livecode at lists.runrev.com>, wrote:
>
> On 11/4/18 4:45 PM, Brian Milby via use-livecode wrote:
>
> My updated solution always looks for overlap but if none are found it uses
> optimized versions of the search (private functions instead of inside the
> main function). I special case for no overlap and a single overlap in the
> delimiter. It is about the same speed as Geoff’s.
>
>
> Nice. I tried to get tricky and replace that 'replace with' loop with a
> 'repeat for each' loop, but ended up about 20% slower. Not at all what I
> expected.
>
> --
> Mark Wieder
> ahsoftware at gmail.com
>
> _______________________________________________
> use-livecode mailing list
> use-livecode at lists.runrev.com
> Please visit this url to subscribe, unsubscribe and manage your
> subscription preferences:
> http://lists.runrev.com/mailman/listinfo/use-livecode
>
>



More information about the Use-livecode mailing list