How to find the offset of the last instance of a repeating character in a string? (Geoff Canyon)

[Brian Milby]

I’m working on an update to the stack now. Moving buttons to the left side to make it easier to add more.

Thanks,
Brian
On Nov 4, 2018, 10:02 PM -0600, Mark Wieder via use-livecode <use-livecode at lists.runrev.com>, wrote:
> On 11/4/18 4:45 PM, Brian Milby via use-livecode wrote:
> > My updated solution always looks for overlap but if none are found it uses optimized versions of the search (private functions instead of inside the main function). I special case for no overlap and a single overlap in the delimiter. It is about the same speed as Geoff’s.
>
> Nice. I tried to get tricky and replace that 'replace with' loop with a
> 'repeat for each' loop, but ended up about 20% slower. Not at all what I
> expected.
>
> --
> Mark Wieder
> ahsoftware at gmail.com
>
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