paul at researchware.com
Sat Jun 2 07:46:46 EDT 2018
Sorry, I missed the all columns bit. Yes, LIMIT is the way to do this
SELECT * FROM valveFlowsA WHERE meterNum =1 AND valveNum =3
ORDER BY iStoreGrp DESC LIMIT 1
If you still need it. The DESC insure the record with the highest (max)
iStoreGrp value is returned first. CAUTION: If the data contained two
records with meterNum =1 AND valveNum =3 and the exact same iStoreGrp
value, I don't believe there is a way to predict which record will be
the first returned. This only works if iStoreGrp is effectively unique
On 6/1/2018 8:48 PM, Mike Bonner via use-livecode wrote:
> if I understand correctly, and just off the top of my head, using "limit"
> is one way to do this...
> The sql pseudo code would be something like: select * from yourtable order
> by iStoreGrp descending where meterNum = 1 AND valveNum = 3 limit 1
> This would grab all the rows, sort them by istoregrp and return the top
> On Fri, Jun 1, 2018 at 6:31 PM, William Prothero via use-livecode <
> use-livecode at lists.runrev.com> wrote:
>> Maybe someone can answer this easily and save me some hair pulling. I know
>> it’s google-able, but I’ve tried and know it’s going to be a trudge to get
>> the right format.
>> I want to make a query to a mySQL db that:
>> The table is named: “valveFlowsA”
>> I want the query to return the row with the maximum of a column named
>> “iStoreGrp” when
>> columns named “meterNum” and “valveNum” are specified. So, with meterNum
>> =1 and
>> valveNum =3, I would get the row for the maximum value of “iStoreGrp”.
>> All of these columns are integers.
>> If anybody has this query in their quiver of tools, please let me know.
>> William A. Prothero
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