Area of Irregular Polygon

Jim Hurley jhurley0305 at sbcglobal.net
Sun Nov 15 03:32:44 EST 2015


Hi Roger,

Actually, the answer to that question I raised follows in the next paragraph. All those terms cancel in pairs.

As someone pointed out, that paragraph is a proof of the validity of the method for calculating the area of a polygon.

You’re probably right about the minus sign.

Jim

> 
> Message: 23
> Date: Sat, 14 Nov 2015 18:37:13 -0800
> From: Roger Guay <irog at mac.com>
> To: How to use LiveCode <use-livecode at lists.runrev.com>
> Subject: Re: Area of Irregular Polygon
> Message-ID: <868CEDF8-5E56-46DC-B88C-BB6A68CD4E8F at mac.com>
> Content-Type: text/plain;	charset=utf-8
> 
> Jim,
> 
> I'm just now trying to catch up on this discussion and I see that no one has answered your question. I can?t answer either and wonder what?s going on???
> 
> BTW, I believe you should have a negative sign in front of the square bracket . . .  not that that helps at all!
> 
> Cheers,
> 
> Roger
> 
> 
> 
> 
>> On Nov 11, 2015, at 2:35 PM, Jim Hurley <jhurley0305 at sbcglobal.net> wrote:
>> 
>> Very interesting discussion. 
>> 
>> However, I was puzzled by the following term in the sum used to calculate the area of a polygon--labeled the centroid method.
>> 
>> x(i)*y(i+1) - x(i+1)y(i)   
>> 
>> Where does this come from? If one were using the traditional method of calculating the area under a curve (perhaps a polygon) the i'th  term in the sum would be:
>> 
>> [x(i+1) - x(i)] * [y(i+1) + y(i)] / 2
>> 
>> That is, the base times the average height. This was the original method employed by many--the non-centroid method
>> 
>> Multiplying this out you get:
>> 
>> x(i)*y(i+1) - x(i+1)y(i) +      [x(i+1)* y(i+1) - x(i)* y(i)]
>> 
>> So THE SAME EXPRESSION as in the centroid method EXCEPT for the added term in square brackets. So, WHY THE  DIFFERENCE?
>> 
>> In calculating this sum all of the intermediate terms in the sum cancel out, leaving just the end terms:  x(n)y(n) - x(1)* y(1)
>> But if the figure is closed, they too cancel each other. 
>> For example:  (x3 * y3 - x2*y2) + (x4*y4 - x3*y3)... Notice that the x3 * y3 terms cancel.
>> 
>> Curiously, if one were attempting to calculate the area under a curve (non-polygon) using this method, the principle contribution could come from just these end point terms. As an extreme example, if the curve began at the origin (x(0) = y(0) = 0),. there would be a substantial contribution from the end point x(n) * y(n), where n is the last point. If it were a straight line, ALL the contribution would come from the end point: x(n) y(n) . Divided  by 2 of course.
>> 
>> Jim
>> 
>> P.S. the centroid of a closed curve might be liken eo the center of gravity in physics.
>> Two closed curves could have the same centroid but very different areas (masses) 
>> The center of mass bears no relation to the mass, and the centroid of a closed curved bears no relation to the area.
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