randomly position objects on-screen

Roger Guay irog at mac.com
Fri May 31 14:08:46 EDT 2013


Ooops that should be + tY in the last line…


On May 31, 2013, at 11:06 AM, Roger Guay <irog at mac.com> wrote:

> Hi Chris,
> 
> I believe this will do it for you:
> 
> on placeBtnRandom pbtnName
>   put the width of btn pbtnName into bW
>   put the height of btn pbtnName into bH
>   put the width of this stack into sW
>   put the height of this stack into sH
>   put random(sW-bW) into tX
>   put random(sH-bH) into tY
>   set the loc of btn pbtnName to bW/2+ tX, bH/2 - tY  
> end placeBtnRandom
> 
> Regards,
> Roger
> 
> On May 31, 2013, at 10:49 AM, Chris Sheffield <cmsheffield at icloud.com> wrote:
> 
>> Okay, I figure someone out there has probably done this before, so I thought I'd ask here before I dive in to the deep end (or go off the deep end, whichever comes first).
>> 
>> Given a rectangular area (in this case a graphic object), I need to randomly position three controls (in this case Scott's tmControl buttons (groups)), within that area. It's not a huge area to work with, but the controls are not too big. The conditions are that the controls cannot intersect (overlap) and they have to be completely visible within the given area (not partially off-screen).
>> 
>> Any takers?
>> 
>> Thanks,
>> Chris
>> 
>> 
>> --
>> Chris Sheffield
>> Read Naturally, Inc.
>> www.readnaturally.com
>> 
>> 
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> 
> 
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