randomly position objects on-screen

Roger Guay irog at mac.com
Fri May 31 14:06:43 EDT 2013

Hi Chris,

I believe this will do it for you:

on placeBtnRandom pbtnName
   put the width of btn pbtnName into bW
   put the height of btn pbtnName into bH
   put the width of this stack into sW
   put the height of this stack into sH
   put random(sW-bW) into tX
   put random(sH-bH) into tY
   set the loc of btn pbtnName to bW/2+ tX, bH/2 - tY  
end placeBtnRandom


On May 31, 2013, at 10:49 AM, Chris Sheffield <cmsheffield at icloud.com> wrote:

> Okay, I figure someone out there has probably done this before, so I thought I'd ask here before I dive in to the deep end (or go off the deep end, whichever comes first).
> Given a rectangular area (in this case a graphic object), I need to randomly position three controls (in this case Scott's tmControl buttons (groups)), within that area. It's not a huge area to work with, but the controls are not too big. The conditions are that the controls cannot intersect (overlap) and they have to be completely visible within the given area (not partially off-screen).
> Any takers?
> Thanks,
> Chris
> --
> Chris Sheffield
> Read Naturally, Inc.
> www.readnaturally.com
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