Bug or just something you can't do ?
    Bob Sneidar 
    bobs at twft.com
       
    Mon Oct  1 12:40:03 EDT 2012
    
    
  
No because you are passing a reference, not the value itself. That is how the otherwise sandboxed command knows about the variable t outside itself. It would otherwise create an entirely new t if you didn't pass by reference. It's my understanding that presently you cannot pass an array element by reference. You can only pass the entire array. 
Instead try passing the entire array, then checking inside your command to see if it is an array and then act accordingly. 
Bob
On Sep 30, 2012, at 4:31 PM, Alex Tweedly wrote:
> So doesn't
>   increment t
> become
>  increment (the value of t)
    
    
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