Performance

[René Micout]

I have also this case : no variable but object (button) name :

   repeat with i = 1 to 21
      put "set the backColor of btn" && quote & "btnHarmo"& i & quote && "to 89,149,218" into vxA ; do vxA
   end repeat

is array solution possible ?

or it is necessary to do :

set the backColor of btn "btnHarmo1" to 89,149,218
set the backColor of btn "btnHarmo2" to 89,149,218
set the backColor of btn "btnHarmo3" to 89,149,218
...
...
set the backColor of btn "btnHarmo21" to 89,149,218


Le 20 juin 2010 à 13:18, Jim Ault a écrit :

> In this case I would use an array
> or custom properties.  Much faster by far.
> 
> --variable array
> add one to vgCpuFlux[ vpNumFlux ]
> 
> 
> --custom property ( a trickier technique, but more powerful )
> 
>   get the vgCpuFlux[ vpNumFlux ] of this stack +1
>   set the vgCpuFlux[ vpNumFlux ] of this stack to IT
> 
> --or store on each card
>   get the vgCpuFlux[ vpNumFlux ] of this CARD +1
>   set the vgCpuFlux[ vpNumFlux ] of this CARD to IT
> 
> ---------------------------------------------------------
> The array method takes 1 tick to do 10,000 times
>   put "4" into vpNumFlux
>   put the ticks into startt
>   repeat 10000 times
>      add one to vgCpuFlux[ vpNumFlux ]
>   end repeat
>   get the ticks - startt
>   get IT & cr & vgCpuFlux[ vpNumFlux ]
>   answer IT -- => 1   yep only one tick
> 
> 
> The custom property method takes 14 ticks to do
>   put "4" into vpNumFlux
>   put the ticks into startt
>   repeat 10000 times
>       get the vgCpuFlux[ vpNumFlux ] of this stack + 1
>      set the vgCpuFlux[ vpNumFlux ] of this stack to IT
>   end repeat
>   get the ticks - startt
>   get IT & cr & the vgCpuFlux[ vpNumFlux ] of this stack
>   answer IT -- => 14 ticks
> 
> The 'do' command should not be used for simply adding numbers such as a cross-tabulation technique like you are employing.
> Hope this helps.
> 
> 
> On Jun 20, 2010, at 3:38 AM, René Micout wrote:
> 
>> Thank you Mark,
>> In my project I use lot of "do" command...
>> For you, is that (the number of flux (flows) is 5) :
>> 
>> put "add 1 to vgCompteurFlux"& vpNuméroduFlux into vxA ; do vxA
>> 
>> faster or slower than :
>> 
>> switch vpNuméroduFlux
>> case 1 ; add 1 to vgCompteurFlux1 ; break
>> case 2 ; add 1 to vgCompteurFlux2 ; break
>> case 3 ; add 1 to vgCompteurFlux3 ; break
>> case 4 ; add 1 to vgCompteurFlux4 ; break
>> case 5 ; add 1 to vgCompteurFlux5 ; break..
>> end switch
>> 
>> You can answer to me : make a test ;-)... But have you ever had this choice to make ?
>> 
> 
> Jim Ault
> Las Vegas
> 
> 
> 
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