Simple Arrays

[Thomas McGrath III]

Pardon my question, but I have learned more about arrays in these four  
posts than I ever thought about before:

So given that I would want a multi-dimensional array where theData[2] 
[3] = "Blue" as in the examples provided, what is the 'best' way to  
enter data into this array, or is the way Bob did it the best way?

Workflow:
First;
>> put "1"&  comma&  "A"&  comma&  "Green"&  return into theData
>> put "2"&  comma&  "B"&  comma&  "Blue"&  return after theData
>> put "3"&  comma&  "C"&  comma&  "Orange"&  return after theData
>> put "4"&  comma&  "D"&  comma&  "White"&  return after theData
Then ;
split theData with cr

Would this get me theData[2][3] = "Blue" ??? I thought the delimiter  
was TAB?

Would this be better:
put "1"& tab& "A"& tab& "Green"& return into theData

OR is this all wrong and if so what is the 'best' way to enter a lot  
data into a mutli-dimensional array to get these results??
Thank you for this.

Tom McGrath III
Lazy River Software
3mcgrath at comcast.net

iTunes Library Suite - libITS
Information and download can be found on this page:
http://www.lazyriversoftware.com/RevOne.html

On Jan 9, 2010, at 9:37 PM, Phil Davis wrote:

> Hi Bob,
>
> On 1/9/10 5:12 PM, Bob Sneidar wrote:
>> Hi all.
>>
>> Apparently I am not getting arrays AT ALL. I would think that given:
>>
>> put "1"&  comma&  "A"&  comma&  "Green"&  return into theData
>> put "2"&  comma&  "B"&  comma&  "Blue"&  return after theData
>> put "3"&  comma&  "C"&  comma&  "Orange"&  return after theData
>> put "4"&  comma&  "D"&  comma&  "White"&  return after theData
>>
>> which would get me:
>> 1,A,Green
>> 2,B,Blue
>> 3,C,Orange
>> 4,D,White
>>
>
> Actually either of these:
>
>    split theData with cr
>    split theData by row -- where the rowDelimiter is CR
>
> would get you this:
>
>    theData[1] = "1,A,Green"
>    theData[2] = "2,B,Blue"
>    theData[3] = "3,C,Orange"
>    theData[4] = "4,D,White"
>
>> I could then split by column (or by row I get confused) and get a  
>> simple array where:
>> theData[1,1] = "1"
>> theData[1,2] = "A"
>> theData[2,1] = "2"
>> theData[4,3] = "White"
>>
>> And so forth. However, this is NOT the case!
>
> Right. Technically speaking, comma is not an array index separator.  
> Commas in our array keys help us conceptually represent multiple  
> array dimensions in our own minds, but Rev sees an array with such  
> keys as a simple one-dimensional array with alphabetic keys (since  
> commas are not numerals).
>
> Until version 3.0, Rev couldn't handle true multi-dimensional  
> arrays. Since then, the thing that tells Rev "this is a multi- 
> dimensional array" is multiple keys per element, with each key in  
> its own bracket. Like this:
>
>    theData[1][1] = "1"
>    theData[1][2] = "A"
>    theData[1][3] = "Green"
>
>
> Now do you see why 'transpose()' wouldn't work with your array? In  
> part it's because your keys aren't numeric - they contain commas.  
> (Also they have to be sequential numbers.)
>
> Welcome to array re-education camp!  ;-)
>
> Phil Davis
>
>
>>  If it were, I could issue a command:
>>
>> put transpose(theData) into myArray
>>
>> and:
>> myArray[1,2] = 2
>> myArray[1,3] = 3
>>
>> and so on. If I got the entire row (I think there's a function for  
>> that) then I would have effectively gotten the column of the  
>> original data. Seems reasonable eh?
>>
>> So can someone please explain to me why I cannot get a simple x,y  
>> row,column grid-like array using these simple commands? Revolution  
>> seems to think that the first column MUST be the key! I would LIKE  
>> for revolution to simply create it's OWN numerical keys and let my  
>> data be my data. Maybe in the future add an argument to the split  
>> and combine commands to tell it whether or not I WANT Revolution to  
>> treat my first column as the key?
>>
>> If arrays worked like I described above, it would be a simple  
>> matter to get a single column of an array, just by transposing it  
>> and getting an entire row, instead of writing complex repeat loops  
>> to get a column of data. Am I missing something here?
>>
>> Thanks for any wisdom you can give. I can save some helpful souls  
>> the trouble of responding by saying I am capable of making repeat  
>> loops to accomplish this. I was just hoping that maybe I was  
>> missing something and I can in fact do what I thought I could.
>>
>> Bob_______________________________________________
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>>
>>
>
> -- 
> Phil Davis
>
> PDS Labs
> Professional Software Development
> http://pdslabs.net
>
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