Multidimensional array issue

[Ralph DiMola]

Also works,

if tArray[“status”] an array -- It's an array

if (not (tArray[“status”] an array)) and (tArray[“status”] is not empty) -- it's a value

Ralph DiMola
IT Director
Evergreen Information Services
rdimola at evergreeninfo.net

-----Original Message-----
From: use-livecode [mailto:use-livecode-bounces at lists.runrev.com] On Behalf Of HENRY LOWE via use-livecode
Sent: Monday, March 08, 2021 7:26 PM
To: Nabble-Livecode-List
Cc: HENRY LOWE
Subject: Re: Multidimensional array issue

Thanks Mark. There are two possible states:

tArray[“status”] holds a value and tArray[“status”][“text”] does not

or

tArray[“status”][“text”] holds a value and tArray[“status”] does not


My code is trying to do the following:

If tArray[“status”] does not hold a value then check if tArray[“status”][“text”] holds a value


The crux is how one reliably determines that an array member (e.g. tArray[“status”]) holds a value?

I would have assumed that if the array member does not hold a value then  - if tArray[member] is empty would always return true. However that does not appear to be the case if the array is multidimensional.


It appears that both tArray[“status”] is an array and tArray[“status”][“text”] is an array are true. Am I missing something about using this syntax?

Thanks,

Henry


> On Mar 8, 2021, at 3:56 PM, Mark Wieder via use-livecode <use-livecode at lists.runrev.com> wrote:
> 
> On 3/8/21 3:46 PM, HENRY LOWE via use-livecode wrote:
> 
>> I have often used the form 'if tArray[“key1”] is empty' to determine whether an array element hold a value but this breaks if tArray[“key1”][“key2”] holds a value.
> 
> Same here. Not that I've every liked that paradigm, just that it's been that way since life crawled out of the ocean.
> 
> However this should do the trick.
> 
> if tArray["status"] is an array then
>  put tArray["status"]["text"] into tStatus else  put tArray["status"] 
> into tStatus end if
> 
> --
> Mark Wieder
> ahsoftware at gmail.com
> 
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