Help with an algorithm...

dsc at swcp.com dsc at swcp.com
Mon Aug 5 18:20:43 EDT 2019


I fixed this to use lists... Maybe.

put parentArray( LISTNEW ) into aNew
put parentArray( LISTOLD )  into aOld
intersect aNew with aOld  -- Remove from aOld that which is not in aNew
union aOld with aNew recursively -- Leaves aNew unchanged except that children in aOld are brought in. I think.
put parentList(  aNew ) into LISTNEW

Parents and children are keys in the arrays built. Children are sub-arrays of parents.

> On Aug 5, 2019, at 12:31 PM, Dar Scott Consulting via use-livecode <use-livecode at lists.runrev.com> wrote:
> 
> I'm pretty sure I goofed somewhere, but maybe something like this?
> 
> intersect ARRAYNEW with ARRAYOLD into temp
> union temp with ARRAYNEW recursively
> 
> 
>> On Aug 5, 2019, at 9:53 AM, Paul Dupuis via use-livecode <use-livecode at lists.runrev.com> wrote:
>> 
>> Today is not my coding day. I have a problem I should be able to design a solution for an am struggling. Clearly I am missing "something"
>> 
>> I have 2 lists (LISTNEW and LISTOLD) of the following format:
>> 
>> ParentA
>> <space>Child 1
>> <space>Child 2
>> <space>etc.
>> ParentB
>> <space>Child 1
>> <space>etc.
>> etc.
>> 
>> The parents are in alphabetical sorted order, the children may not be in sorted order
>> 
>> I need to hunt through LISTOLD comparing the LISTOLD Parents to the LISTNEW Parents
>>  FOR any LISTOLD Parent present in LISTNEW, check the Children of the matching Parents and add any Child for the LISTOLD Parent that is not already under its matching LISTNEW Parent
>>  FOR any LISTOLD Parent NOT in LISTNEW, I can ignore the Parent and its Children
>> 
>> I can not seem to write an approach to solve this today. Does any body have some code so solve this they may be willing to share?
>> 
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> 
> 
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