Help with an algorithm...

Paul Dupuis paul at researchware.com
Mon Aug 5 13:46:24 EDT 2019


I had not considered using arrays. I have no idea why, as it provides a 
mechanism. Just not thinking well today. Thanks for the tip!


On 8/5/2019 1:40 PM, dunbarx--- via use-livecode wrote:
> Hi.
> This seems like a good case for arrays (pseudo):
> You have to create an array for each parent. The only way i see to find those is to go through the list looking for lines that DO NOT start with a space. If you work from the bottom up, since children are always at the bottom and they always have spaces in front, you can find the lastMost parent.
> Set the itemDel to that parent, and isolate the last item. This will be a list of children of that parent.
> See if there is a corresponding parent in the new list, and isolate that "item" list of children.
> Run through the children of the old list and see if they live in the new list. If they do, add them:The array part is something like:
> put oldChildren & return & newChildren into allChildrenrepeat for each line tLine in allChildrenput tLine into myArray[tLine]
>
> Delete the last item of the old list and do it again. This way the last item can be isolated directly.
> Craig
>
> -----Original Message-----
> From: Paul Dupuis via use-livecode <use-livecode at lists.runrev.com>
> To: How to use LiveCode <use-livecode at lists.runrev.com>
> Cc: Paul Dupuis <paul at researchware.com>
> Sent: Mon, Aug 5, 2019 11:53 am
> Subject: Help with an algorithm...
>
> Today is not my coding day. I have a problem I should be able to design
> a solution for an am struggling. Clearly I am missing "something"
>
> I have 2 lists (LISTNEW and LISTOLD) of the following format:
>
> ParentA
> <space>Child 1
> <space>Child 2
> <space>etc.
> ParentB
> <space>Child 1
> <space>etc.
> etc.
>
> The parents are in alphabetical sorted order, the children may not be in
> sorted order
>
> I need to hunt through LISTOLD comparing the LISTOLD Parents to the
> LISTNEW Parents
>     FOR any LISTOLD Parent present in LISTNEW, check the Children of the
> matching Parents and add any Child for the LISTOLD Parent that is not
> already under its matching LISTNEW Parent
>     FOR any LISTOLD Parent NOT in LISTNEW, I can ignore the Parent and
> its Children
>
> I can not seem to write an approach to solve this today. Does any body
> have some code so solve this they may be willing to share?
>
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