How to find the offset of the last instance of a repeating character in a string? (Geoff Canyon)
alex at tweedly.net
Fri Nov 2 22:10:36 EDT 2018
On 03/11/2018 00:43, Geoff Canyon via use-livecode wrote:
> I like that, changing it. Now available at
> One thing I don't see how to do without significantly impacting performance
> is to return all offsets if there are overlapping strings. For example:
> would return 1,5, when it might be reasonable to expect it to return 1,3,5.
> Using the offset function with numToSkip would make that easy; adapting
> allOffsets to do so would be harder to do cleanly I think.
Can I suggest changing it to "someOffsets()" :-) :-)
But seriously, can you not iteratively run "allofsets" ?
something like .... (typed straight into email - totally untested)
function allOffsets pDel, pStr
repeat with c = 1 to 255 -- or some other upper limit ?
if NOT pDel contains numtochar(c) then
put numtochar(c) into c
put someOffsets(pDel, pStr) into newR
if the number of items in newR = 0 then exit repeat
repeat for each item I in newR
put c into char I of newR
put newR after R
sort items of R numeric
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