is evaluation order defined, and evaluation of conditionals"and" to "or

[Dr. Hawkins]

On Monday, June 25, 2012, wrote:
>
>
> "or" is a simpler case, as there is never a need to evaluate after
> a first round "true". Again, at least externally.
>

No, they're not.

OR is "when both inputs are false, output is false (else its true)"
AND is "when both inputs are true, output is true (else its false)"

(ok, so I discovered DeMorgan's theorem myself as a kid when I didn't have
the chips I needed (although I expressed it as "invert all the inputs and
the output, and use the other name"



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