Counting and numbering duplicates in a list

[Peter M. Brigham, MD]

function flagDupes tList
   put tList into scratchList
   repeat for each line t in tList
      if t is among the lines of scratchList or \
             freqArray[t] > 0 then
         add 1 to freqArray[t]
         put cr & t & "-" & freqArray[t] after outputList
      else
         put cr & t after outputList
      end if
      delete line 1 of scratchList
   end repeat
   delete char 1 of outputList
   return outputList
end flagDupes

I *think* this should be fast with large lists.

-- Peter

Peter M. Brigham
pmbrig at gmail.com
http://home.comcast.net/~pmbrig


On Sep 28, 2011, at 10:52 PM, Roger Eller wrote:

> There are several ways I could approach this, but I'm unsure which way is
> best?  I have a list of numbers that 'may' contain duplicates.  I need to
> sequence ONLY the duplicates without changing the order the list. If there
> is only one, it does not need to be sequenced.
> 
> Should I just repeat, and keep the content of line x in a variable, then add
> 1 to a sequence variable if the number is encountered again?  Is there a
> better way?  Simple stuff, I know, but these lists can be really long, and I
> want it to process as quickly possible.
> 
> 12345
> 12345
> 12344
> 12333
> 10112
> 12333
> 
> must become:
> 
> 12345-1
> 12345-2
> 12344
> 12333-1
> 10112
> 12333-2
> 
> ˜Roger
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