Selecting an object

[Peter Haworth]

Thanks.  I guess the way I was doing it was mimicking how I would do it manually in the IDE but your way sounds neater so I'll give it a whirl.

Pete Haworth

On Mar 13, 2011, at 9:50 PM, J. Landman Gay wrote:

> On 3/13/11 11:43 PM, J. Landman Gay wrote:
>> On 3/13/11 7:45 PM, Peter Haworth wrote:
>>> I know that was suggested and I can't remember why it didn't work for
>>> me - I think it may have been because the group may not exist. Or
>>> maybe it's because I'm copying the control into the group, not
>>> creating it?
>> 
>> For copying, use this:
>> 
>> copy button "myButton" to grp "mygroup" of cd "thatCard"
> 
> Oops, this will fail if you aren't on that card. I should have said:
> 
>  copy button "myButton" of cd "thatCard" to grp "mygroup" of cd "thatCard"
> 
> But there's a shorter way using the "currentCard" syntax. That's sort of like defaultstack, only for cards. So you could set that first, do the work, then set it back:
> 
> put the number of this cd into tOrigCard
> set the currentcard of this stack to "thatCard"
> copy btn "myButton" to grp "mygroup"
> ... anything else you need to do there
> set the currentcard of this stack to tOrigCard
> 
> So all the work gets done without the user ever changing cards.
> 
>> 
>> If you no longer want the original, you'd need to delete it after that:
>> 
>> delete button "myButton" of cd "thatCard"
>> 
>> If the group doesn't exist then you'd need to create one first. You can
>> do that remotely too:
>> 
>> create grp "new group"
>> place grp "new group" onto cd "thatCard"
>> remove grp "new group" from this cd
>> 
> 
> 
> -- 
> Jacqueline Landman Gay         |     jacque at hyperactivesw.com
> HyperActive Software           |     http://www.hyperactivesw.com
> 
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