Efficiency question for list modification

[Jim Ault]

Of course, using a faster processor would give faster results.
What would be the speed difference if the data block was sent to an  
irev script and run on a faster processor?

Jim Ault
Las Vegas

On Mar 10, 2011, at 12:07 PM, Alex Tweedly wrote:

> use repeat for each line L ... and collect the modified lines in a  
> separate variable, replace the original variable after the loop
>
> repeat fer each line L in tData
>   put ... & CR after temp
> end repeat
> put temp into tData
>
> should be very quick.
>
> -- Alex.
> btw - not needed in this case, but you could use split/combine in  
> it's "single separator" form
> split tData by CR
> repeat with i = 1 to the number of lines in the keys of tData
>   put .... into tData[i]
> end repeat
> combine tData by CR