repeat with i=

[J. Landman Gay]

On 7/14/11 10:06 AM, Ronald Zellner wrote:
> Jim's seems to be the most efficient and accurate,

I agree. Sorting the list before the loop and then peeling off the items 
one by one is the most efficient way to do it. I mentioned "any" because 
it's such a nice addition to the language, but I didn't mean to endorse 
it for this situation.

-- 
Jacqueline Landman Gay         |     jacque at hyperactivesw.com
HyperActive Software           |     http://www.hyperactivesw.com