How do you do it??

[Mike Bonner]

Well yeah because "do" is a unit.  part fails, all fail so the AA never
gets to the msg box. Explanation still stands though.


On Fri, Dec 23, 2011 at 3:29 PM, Bob Sneidar <bobs at twft.com> wrote:

> It won't even put AA into the message box. It will try to compile the
> entire do statement first, and upon failing will just throw an error.
>
> Bob
>
>
> On Dec 23, 2011, at 1:58 PM, Mike Bonner wrote:
>
> > put AA
> > BB into temp2
> > So it will put AA into the message box, and error out on the next line
> > since there is no handler named BB
>
>
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