How do you do it??
bonnmike at gmail.com
Fri Dec 23 17:41:15 EST 2011
Well yeah because "do" is a unit. part fails, all fail so the AA never
gets to the msg box. Explanation still stands though.
On Fri, Dec 23, 2011 at 3:29 PM, Bob Sneidar <bobs at twft.com> wrote:
> It won't even put AA into the message box. It will try to compile the
> entire do statement first, and upon failing will just throw an error.
> On Dec 23, 2011, at 1:58 PM, Mike Bonner wrote:
> > put AA
> > BB into temp2
> > So it will put AA into the message box, and error out on the next line
> > since there is no handler named BB
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