Loop through Multi-Dimensional Array
Michael Kann
mikekann at yahoo.com
Mon Jun 21 13:00:36 EDT 2010
Andrew,
At first glance I think the problem is that if you use "repeat for each" you can't make a change to anything inside that loop. You have to kick what you are changing out to another variable.
This is the main idea:
repeat for each line k in v
if line k is target_line then
put new_line & cr after h
else
put line k & cr after h
end
end repeat
delete last char of h -- last cr
now the variable h holds what you need
--- On Mon, 6/21/10, Andrew Kluthe <andrew at rjdfarm.com> wrote:
> From: Andrew Kluthe <andrew at rjdfarm.com>
> Subject: Loop through Multi-Dimensional Array
> To: use-revolution at lists.runrev.com
> Date: Monday, June 21, 2010, 11:45 AM
>
> Hey there,
>
> I have a multi-dimensional array that uses numbers as the
> first element and
> a string as the second.
>
> Like this:
>
> tleaseData[1]["TenantName]
> tleaseData[1]["TenantContact"]
>
>
> What I need to do is loop through each number element and
> then loop through
> each string element. If the data in the String Element
> equals the Data in my
> pName Paramater, I need to replace the data in the array
> with the parameter
> pNewName
>
> The numbered loop isnt a problem as I use with x=1, but how
> do I nest a loop
> to
>
> This is the jist of what I have been doing, but I cannot
> get the newName to
> replace the old in the array. I think its an issue of
> referencing the switch
> properly.
>
> function CheckRecords pName, pNewName
>
> repeat with x=1 to the number of elements in tleaseData
>
> repeat for each element i in tleaseData[x]
> if i is pName then
> -- The Loop
> Enters Here Just Fine Where It Should --
> put pNewName into
> i
> -- It does not do
> this ^^^
> put true into
> tleaseData[x]["Changed"]
> -- It does this
> ^^^
> end if
> end repeat
>
> end repeat
> end CheckRecords
>
> Why isn't i becoming pNewName? Am I referencing that put
> correctly? Am I
> supposed to be putting into i?
> --
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> Nabble.com.
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