bitXor 8 bytes of data
neil at yippo.co.uk
Wed Dec 9 14:48:51 EST 2009
After some deep thought today, I achieved my desired goal by xoring each
individual byte. I could swear I tried this before, but anyhoo it's working
put byte 5 to 12 of tPointData into tEncLat -- read out lats, lons and keys
from 129 bytes of tPointData
put byte 13 to 20 of tPointData into tEncLon
put Byte 127 of tPointData into tKey1 -- get Encryption bytes from
put byte 128 of tPointData into tKey2
put byte 129 of tPointData into tKey3
-- decrypt lat
replace byte 4 of tEncLat with numToByte((byteToNum(byte 4 of tEncLat)
bitXor (byteToNum(tKey1)))) in tEncLat
replace byte 5 of tEncLat with numToByte((byteToNum(byte 5 of tEncLat)
bitXor (byteToNum(tKey2)))) in tEncLat
replace byte 6 of tEncLat with numToByte((byteToNum(byte 6 of tEncLat)
bitXor (byteToNum(tKey3)))) in tEncLat
Thanks anyway, I was starting to panic after promising an alpha before
From: "Alex Tweedly" <alex at tweedly.net>
To: "How to use Revolution" <use-revolution at lists.runrev.com>
Sent: Wednesday, December 09, 2009 12:04 AM
Subject: Re: bitXor 8 bytes of data
> Neil Allan wrote:
>> Does anyone have a way of doing a "simple" bitwise xor with two 8 byte
>> signed floating point numbers?
>> I believe the revTalk bitXor command can only accept non signed
>> I have tried performing the bitXor byte by byte on the two strings using
>> the byteToNum() function on each byte individually but the result is
>> quite different to what one would get banging the hex equivalent of the
>> string into "calculator" on windows.
>> Calculator gives me the correct answer. I set it to hex mode then just
>> type in the 8 bytes of hex, hit xor, type in the other hex string and "="
>> Any Ideas?
> bitXor() will do what you want. Can you show a more complete code
> fragment (including the data you used) and we'll see if it's something
> about how you're setting the data up ?
> -- Alex.
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