calendar function anyone ?
Sarah Reichelt
sarah.reichelt at gmail.com
Wed Feb 14 17:08:17 EST 2007
When you are working with dates only, the dateItems will usually show
the hour as 2 am, but sometimes as 1 am depending on daylight savings.
To avoid any potential cross-overs, when working with dates alone, I
tend to supply a default time of midday. The convert command will not
mess this up by supplying it's own default and since it is in the
middle of the day, I know the date will be correct.
Re-writing my suggested function allowing for this:
function weekDay pDate
put pDate && "12:00 pm" into tDate
convert tDate to dateItems
put the last item of tDate into tDayNum
put line tDayNum of the system weekdayNames into tDayName
return tDayName
end weekDay
I think you will find this completely reliable.
As an aside on the convert command: I have issues with the way convert
automatically applies the current time zone when converting seconds so
that a specific number of seconds refers to a moment in time and not
to a set date & time. This makes the seconds useless to me as a data
storage & transfer device since the conversions will vary from machine
to machine depending on time zones etc. I now store all time stamps in
a 14 digit number YYYYMMDDHHMMSS. However once I have this data, date
& time calculations can be done locally with the convert command only
being used to produce temporary variables, not long-term data storage.
Cheers,
Sarah
> Thanks for your reply. Converting the date to dateItems actually crossed
> my mind, but are you sure the convert function is 100% bug free ?
> AFAIR, last time I used it in a cgi script, there was a 60 min difference
> in some conversions (unfortunately I don't remember in which cases, but
> I remember that this bug lead to a few threads on this list) and finally choosed
> to make all date conversions with mySQL instead...
>
> Best,
> JB
>
> > > Does anyone know of a function to find out, for instance, which day of
> > > the
> > > week was sept. 18th 1918 or which day of week will be dec. 5th 2025 ?
> > >
> >
> > If you convert a date to dateItems, it becomes a comma-delimited list
> > of 7 items. The last one is a number indicating the day of the week.
> > Then you can use the system weekDayNames to find the day name that
> > matches that number.
> >
> > e.g.
> > put "12/5/2025" into tDate
> > convert tDate to dateItems
> > put the last item of tDate into tDayNum
> > put line tDayNum of the system weekdayNames into tDayName
> >
> > Cheers,
> > Sarah
>
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