AW: counting runs
Thomas Fischer
fischer at mail.sub.uni-goettingen.de
Mon Oct 31 22:28:50 CST 2005
Hi Jason,
if you just want to count the occurrences of H and T in strings like
> T,T,H,T,T,H,H,H,T,T,H,T,H,H,H,T,H,T,H,T
the easiest (and most likely fastest, unchecked though) way might be to do something like
put "T,T,H,T,T,H,H,H,T,T,H,T,H,H,H,T,H,T,H,T" & comma into myString
put the number of items in myString into totalCount
replace "T," with "" in myString
put the number of items in myString into headCount
put totalCount - headCount into tailCount
answer "total: " & totalCount & return & \
"Heads: " & headCount & return & \
"Tails: " & tailCount
All the best
Thomas
--
Thomas Fischer
Salzburg
> -----Ursprungliche Nachricht-----
> Von: use-revolution-bounces at lists.runrev.com
> [mailto:use-revolution-bounces at lists.runrev.com]Im Auftrag von Jason
> Tangen
> Gesendet: Dienstag, 1. November 2005 01:22
> An: use-revolution at lists.runrev.com
> Betreff: counting runs
>
>
> Hello,
>
> I'm trying to solve a seemingly simple problem and I could use some
> help. A coin flip will come out "Heads" or "Tails" and will produce,
> for example, the following series for 20 flips:
>
> T,T,H,T,T,H,H,H,T,T,H,T,H,H,H,T,H,T,H,T
>
> I need to count up the number events for a particular run. For example,
>
> Heads x 3 = 2
> Heads x 2 = 0
> Heads x 1 = 4
> Tails x 1 = 4
> Tails x 2 = 3
> Tails x 3 = 0
>
> I need to account for runs up to 60 (rather than 3 above) for
> hundreds of flips (rather than 20 above).
>
> I've been using a very clumsy multiple if-then solution to date, but
> this quickly becomes difficult with many runs.
>
> Can someone point me in the right direction?
>
> Cheers,
> Jason
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