Regex help, please

[Dave Cragg]

On 11 Oct 2005, at 00:04, Harvey Toyama wrote:

> Hi,
>
> I have a log file to parse. The data looks like this:
>
>                                                       Chip_Test:
>
>   2   1075.7  R120<-7000h                    00020000         mov
> HifRegs
>   2   1088.1  R14<-7000h                     00020002         mov
> HifRegs
>   6   1100.5  [7020h]<-1h                    00020004         mov
> RSTS_Busy
>
>
> I do not want to capture the line with "Chip_Test:". I know the third
> character will always be a single digit number. I have a feeble
> knowledge of Regex from casual Unix use. I thought something like this
> would work
>
>             put line vLineCounter into vLineBuffer
>             if char 3 of vLineBuffer = "[0-9]" then
>             ...


regEx in Rev is only used in the MatchText and ReplaceText functions.

You could do this:

   if char 3 of vLineBuffer is a number then

But you're missing something in the first line. Assuming vLineCounter  
is a number, and the data to parse is in a variable named vData, then  
you need something like this:

   put line vLineCounter of vData into vLineBuffer


If you're parsing through all the lines in the file, and if it's  
long, you'll find that the expression "line vLineCounter of vData"  
takes longer to evaluate as the value of vLineCounter gets higher. In  
that case, the "repeat for each" format would be a lot faster.  
Something like:

   repeat for each line vLine in vData
     if char 3 of vLine is a number then
     -- your stuff
     end if
   end repeat

Cheers
Dave