counting empty items

[Pierre Sahores]

Hello There,

and..., even without parentheses, tab&tab&tab&tab&a will return 4, just 
because the non empty fourth item will force its evaluation...

Best Regards,

Le 24 mai 04, à 19:46, J. Landman Gay a écrit :

> On 5/24/04 12:09 PM, rand valentine wrote:
>
>>  If I do this:
>> set the itemDelimiter to tab
>> put the number of items of tab & tab & tab & tab
>>  1 is returned.
>> why not 4? I don't get it.
>>  -- if I do this:
>> set the itemDelimiter to tab
>> put empty into item 4 of testVariable
>> put the number of items of testVariable
>>  3 is returned.
>> why?
>
> Because without forcing the compiler to parse the tabs in the first 
> case, each tab is considered a text string. The concatenation looks 
> like this:
>
>  "tabtabtabtab"
>
> If you put parentheses around it, the compiler will evaluate the 
> constants first before working with the string:
>
>   put the number of items of (tab & tab & tab & tab)
>
> Gives 4.
>
> -- 
> Jacqueline Landman Gay         |     jacque at hyperactivesw.com
> HyperActive Software           |     http://www.hyperactivesw.com
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>
-- 
Bien cordialement, Pierre Sahores

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