Targeting function

[Dar Scott]

On Sunday, June 29, 2003, at 05:02 AM, curry wrote:

> The input could be gun location, bullet speed, target location, target 
> direction, and target speed. The output could be bullet direction or 
> collision point.

Try this.  If you get bogged down, let us know.

Your direction and speed is your velocity vector.  In your preliminary 
algebra & trig change it from angle & speed to x-speed & y-speed.  Do 
this for both bullet and target.

Your location, presumably, is already in cartesian coordinates and will 
have components x-location and y-location.  This applies to both the 
gun and the target at any time.

Now that x and y are split out, they can be solved separately.

Set up your location equations based on time and velocity.

Solve the simultaneous equations where the x-location of the target and 
the x-location of the bullet are equal and the same for y.

When you are done, you should have a bullet angle formula with some 
trig and arithmetic.

This makes for a very smart opponent, of course.

Dar Scott