determining array lengths
Jan Schenkel
janschenkel at yahoo.com
Sat Sep 21 16:21:01 EDT 2002
Hi Brad,
I looked into this a while ago. My solution was:
1) If the second dimension is fixed (always NN
elements), you can suffice by saying:
put (the number of lines of the keys of tArray / NN)
2) If however NN is variable, you can get it with the
following trick:
put the keys of tArray into tKeys
split tKeys using return and comma
put the number of lines of the keys of tKeys
I know it looks convoluted, but it works, even if the
second dimension varies.
Hope this helped,
Jan Schenkel.
(You can find the entire thread at the URL:
http://lists.runrev.com/pipermail/use-revolution/2002-August/006786.html
)
--- Brad Allen <BradAllen at mac.com> wrote:
> After looking around in the documentation, I haven't
> been able to
> find a simple function to determine the number of
> keys for a given
> array dimension. Do I need to parse the output of
> the keys function
> for this, or have I overlooked something in the
> documentation?
>
> I was hoping the number function might do it, as in
>
> the number of keys in myArray
>
> The expected output would be something like
> [100,50], to indicate the
> dimensions of the array.
>
> The "number of lines in the keys of myArray" only
> works for
> one-dimensional arrays.
>
> Thanks...
> _______________________________________________
> use-revolution mailing list
> use-revolution at lists.runrev.com
>
http://lists.runrev.com/mailman/listinfo/use-revolution
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